¯3 x 5 + ¯36 ÷ ¯3 -- ¯7 — 10 + 6 x ¯8 ÷ ¯24 —1 =

Your symbols are not understood. What is ¯ ?

Also, show where parentheses go.

I'm sorry the computer jammed and I couldn't do anything-

the problem is List the center, vertices, and foci of hyberbola for following equation:
(y-2)^2/36 - (x-8)^2/64 = 1
b=6
a=8
Center(8,2)
Vertices=(h,k+b) (h,k-b)=(8,8) (8,-4)
Foci =(h +-c,k)
c^2 = a^2 + b^2
c^2 = 64 + 36
c^2 = 100
c=10
8+10=18
foci=(18,2) (-2,2)

I think I did the vertices and foci incorrect

This is a verticl hyperbola, correct?
So formula for vertices would be (h, k+-a)=(8,2+-6)=(8,8) (8,-4)

Foci should be c^2 = a^2 + b^2
8^2 + 2^2 = 64+36
c=10
foci=(8,2+-10)
(8,-8)
(8,12)

To simplify this expression, we need to follow the order of operations which is represented by the acronym "PEMDAS" or "BODMAS." This acronym stands for Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right). We will evaluate the expression step by step:

Step 1: Parentheses (no parentheses in the expression)
Step 2: Exponents (no exponents in the expression)
Step 3: Multiplication and Division (from left to right)
- In the expression, we have ¯3 x 5 = ¯15.
- Next, we have ¯36 ÷ ¯3 = 12.
- Lastly, we have 6 x ¯8 ÷ ¯24 = ¯2.
So far, the expression becomes: ¯15 + 12 - ¯7 - 10 + ¯2 - 1.

Step 4: Addition and Subtraction (from left to right)
- ¯15 + 12 = ¯3.
- ¯3 - ¯7 = 4.
- 4 - 10 = ¯6.
- ¯6 + ¯2 = ¯8.
- ¯8 - 1 = ¯9.

Therefore, the simplified value of the given expression is ¯9.