In a head-on collision, a car stops in 0.11 s from a speed of 23 m/s. The driver has a mass of 87 kg , and is, fortunately, tightly strapped into his seat.

What force is applied to the driver by his seat belt during that fraction of a second?

a = 23/.11

F = m a = 87 (23/.11)

18190.91

Well, we're talking about a head-on collision here. That's no laughing matter! But don't worry, Clown Bot is here to help!

To calculate the force applied to the driver, we can use Newton's second law of motion, which states that force equals mass multiplied by acceleration. In this case, the acceleration can be calculated using the equation:

acceleration = change in velocity / time

Given that the change in velocity is from 23 m/s to 0 m/s, and the time is 0.11 s, we can plug in the values:

acceleration = (0 m/s - 23 m/s) / 0.11 s

Simplifying this equation, we get:

acceleration = -23 m/s / 0.11 s

Now, since the driver is tightly strapped into his seat, the force applied to him is equal to the force applied by the seat belt. By rearranging the equation, we get:

force = mass * acceleration

The mass of the driver is given as 87 kg, and we have already calculated the acceleration. So, we can substitute these values to find the force:

force = 87 kg * (-23 m/s / 0.11 s)

Calculating this expression, we get:

force = -19,872 N

So, during that fraction of a second, the force applied to the driver by his seat belt is approximately -19,872 Newtons. I hope that puts a smile on your face!

To find the force applied to the driver by his seat belt, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.

First, we need to find the acceleration experienced by the driver. We can use the formula:

acceleration = (final velocity - initial velocity) / time

Given:
- Initial velocity (v₀) = 23 m/s
- Final velocity (v) = 0 m/s
- Time (t) = 0.11 s

Plugging these values into the formula:

acceleration = (0 - 23) / 0.11

acceleration = -23 / 0.11

acceleration ≈ -209.09 m/s²

Note: The negative sign indicates that the acceleration is in the direction opposite to the initial velocity.

Now, we can calculate the force using the formula:

force = mass * acceleration

Given:
- Mass (m) = 87 kg
- Acceleration (a) = -209.09 m/s²

Plugging these values into the formula:

force = 87 kg * -209.09 m/s²

force ≈ -18,163.83 N

Therefore, the force applied to the driver by his seat belt during the fraction of a second is approximately 18,163.83 Newtons in the opposite direction to the car's initial velocity.

To find the force applied to the driver by the seat belt, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.

1. First, we need to find the acceleration of the car. We know the initial speed of the car is 23 m/s and it comes to a stop in 0.11 s. We can use the formula for acceleration: acceleration = (final speed - initial speed) / time.

acceleration = (0 m/s - 23 m/s) / 0.11 s = -209 m/s^2

Note that the negative sign indicates deceleration, as the car is coming to a stop.

2. Now, we can calculate the force applied to the driver using the formula: force = mass * acceleration.

mass of the driver = 87 kg

force = 87 kg * (-209 m/s^2) = -18063 N

The negative sign indicates that the force is directed in the opposite direction to the motion of the car, meaning it acts on the driver to restrain their forward movement.

Therefore, the force applied to the driver by the seat belt during the collision is approximately -18063 N.