A force of 0.053 N is required to move a charge of 36 µ a distance of 30 cm in a uniform electric field. What is the size of the electric potential difference between the two points?
Well, well, well, it seems we have a little physics problem here! Don't worry, I'll do my best to give you an electrifying answer!
To find the electric potential difference (also known as voltage), we can use the formula:
V = W/q
Where V is the electric potential difference, W is the work done by the electric field, and q is the charge.
Now, the work done, W, is given by the formula:
W = F * d
Where F is the force and d is the distance.
So, let's plug in the values we have! We have a force of 0.053 N and a distance of 30 cm (which we'll convert to meters by dividing by 100).
W = 0.053 N * (30 cm / 100) m = 0.0159 N∙m
Next, we need to convert the charge of 36 µC (that's microcoulombs) to coulombs. Remember, 1 µC = 10^(-6) C.
q = 36 µC * (1 C / 10^(-6) µC) = 0.000036 C
Now we'll plug these values into the formula for electric potential difference:
V = (0.0159 N∙m) / (0.000036 C)
And after some number crunching, we get:
V ≈ 441.67 volts
So, the electric potential difference between the two points is approximately 441.67 volts. Shocking, isn't it? Keep those electrons flowing smoothly!
To find the electric potential difference between two points, we can use the formula:
ΔV = F * d
Where:
ΔV is the electric potential difference
F is the force applied
d is the distance over which the force is applied
Given:
Force (F) = 0.053 N
Charge (q) = 36 µC = 36 * 10^-6 C
Distance (d) = 30 cm = 30 * 10^-2 m
First, let's convert the charge to Coulombs:
q = 36 * 10^-6 C
Now, we can calculate the electric potential difference:
ΔV = F * d
= q * d
Substituting the given values:
ΔV = (36 * 10^-6 C) * (30 * 10^-2 m)
= (36 * 10^-6 C) * (0.3 m)
= 10.8 * 10^-6 C * m
Simplifying, we get:
ΔV = 10.8 * 10^-6 C * m
= 10.8 * 10^-6 V * m
= 10.8 µV * m
Therefore, the electric potential difference between the two points is 10.8 µV * m.
To find the size of the electric potential difference between the two points, we can use the formula:
Electric Potential Difference (V) = Work done (W) / Charge (Q)
First, let's find the work done (W) using the formula:
W = Force (F) * Distance (d)
Given:
Force (F) = 0.053 N
Distance (d) = 30 cm = 0.30 m
W = 0.053 N * 0.30 m
W = 0.0159 J
Next, we need to find the charge (Q). We are given that a force of 0.053 N is required to move a charge of 36 µC (microcoulombs). To convert microcoulombs to coulombs, we divide by 1,000,000:
Charge (Q) = 36 µC / 1,000,000
Q = 0.000036 C
Now we can substitute the values into the formula to find the electric potential difference (V):
V = W / Q
V = 0.0159 J / 0.000036 C
Calculating this value:
V ≈ 441.67 V
Therefore, the size of the electric potential difference between the two points is approximately 441.67 volts (V).
F * d = q * V
V = F * d / q
= .053 * .3 /36*10^-6
= 5.3 * 10^-2 * 3 * 10^-1 *10^6/36
= .442 * 10^3
= 442 volts