Biology

posted by .

In an experiment designed to measure the distance a golf ball is hit by clubs made of different material, a standardized variable would be:

A The distance the golf ball traveled
B The type of material the club is made of
C The material the golf ball was made of
D The wind direction when the experiment took place
E Both the wind direction when the experiment took place and the material the golf ball was made of are correct

I think it is b but for some reason I am thinking it may be wrong.

  • Biology -

    If by "standardized variable" you mean the variables that need to be controlled, E is the answer. A is the dependent variable and B is the independent variable.


    An independent variable is the potential stimulus or cause, usually directly manipulated by the experimenter, so it could also be called a manipulative variable.

    A dependent variable is the response or measure of results.

    Extraneous variables — other than the independent variable — potentially can affect the dependent variable, so they must be controlled. If possible, you try to keep them constant between the experimental and control group.

    The experimental group receives the independent variable.

    The control group is similar to experimental, except it does not receive the independent variable. Extraneous variables are balanced between experimental and control groups.

  • Biology -

    e is the answer, need help with my bisc 102 biology call me 6629346686

  • Biology -

    its A

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. physics - please help

    A golf ball of mass 0.045 kg is hit off the tee at a speed of 48 m/s. The golf club was in contact with the ball for 5.4 10-3 s. (a) Find the magnitude of the impulse imparted to the golf ball. (b) Find the magnitude of the average …
  2. physics

    When a 0.045 kg golf ball takes off after being hit, its speed is 35 m/s. A)How much work is done on the ball by the club?
  3. physics

    The physics of a golf ball and kinetic energy. When a 0.045 kg golf ball takes off after being hit, its speed is 41 m/s. a) What is the kinetic energy of the ball after it has been hit?
  4. Science

    A golf ball was hit and projected in an angle of 60 degrees with the horizontal. if the initial velocity of the ball was 50m/s, calculate the following: a. the time the golf ball was in the air b. horizontal distance the ball traveled …
  5. physics

    A golf club strikes a 0.040-kg golf ball in order to launch it from the tee. For simplicity, assume that the average net force applied to the ball acts parallel to the ball’s motion, has a magnitude of 7950 N, and is in contact with …
  6. Physics

    A golf club strikes a 0.041-kg golf ball in order to launch it from the tee. For simplicity, assume that the average net force applied to the ball acts parallel to the ball's motion, has a magnitude of 6400 N, and is in contact with …
  7. PHYSICS

    A golf club strikes a 0.041-kg golf ball in order to launch it from the tee. For simplicity, assume that the average net force applied to the ball acts parallel to the ball's motion, has a magnitude of 6400 N, and is in contact with …
  8. Physics

    A golf club strikes a 0.040-kg golf ball in order to launch it from the tee. For simplicity, assume that the average net force applied to the ball acts parallel to the ball's motion, has a magnitude of 7050 N, and is in contact with …
  9. Algebra

    A golf ball is struck by a​ 60-degree golf club at an initial velocity of 84 feet per second. The height of the golf ball in feet is given by the quadratic function h(x)= 16 x^2/(42)^2+72.7/42x where x is the horizontal distance …
  10. physics

    a golf club strikes a 0.045kg golf ball in order to launch it from the tee. For simplicity,assume that the average net force applied to the ball acts parallel to the ball's motion, has a magnitude of 6800N and in contact with the ball …

More Similar Questions