# precalculus

posted by .

solve the logarithm equation show work.

log_7(x-8)- log_7(x-2)=1

• precalculus -

log7 [(x-8)/(x-2)] = 1

[(x-8)/(x-2)] = 7*1 = 7

x - 8 = 7 x - 14

6 x = 6
x = 1

## Similar Questions

1. ### Algebra

log_7 1 = ???
2. ### Math - Logarithm

Solve the following equation. Please show all of your work. 5 ln 2x = 10
3. ### Math - Logarithm

Solve the following logarithm equation. Please show all of your work. log (5 + x) – log(x – 2) = log 2
4. ### precal

use the properties to find the exact value'log_7(343.7 ^15)
5. ### algebra

Solve the equation below. Please show all of your work log_7(x + 3/7) = -2
6. ### pre calculus

Use properties of logarithms to find the exact value of the expression log_7 (343 * 7^15)
7. ### precalculus

solve the following equation show all work log4(x-4)= -1.
8. ### precalculus

solve the following exponential equation. show all work. 4^(4x+2)= 1/64
9. ### precalculus

write the expression below as a single logarithm show work. ln(x-7/x^2+12x+36)-ln(x^2-49/x+6)
10. ### college alg

solve the following logarithm equation log (4x+7)=1+log(x-6) x=?

More Similar Questions