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how would you solve for y in this problem: ln(y1)ln2 = x +lnx ln(y1)ln2 = x +lnx Solve for y... ln[(y1)/2]]=x + lnx take the antilog of each side (y1)/2= e^(x+lnx) solve for y. 
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Let u=lnx and v=lny. Write the expression ln3√x/2y in terms of u and v. For example, lnx^3y=lnx^3+lny=3lnx +lny= 3u+v.