posted by anna .
a hydraulic lift is designed for a gain of 100, so that a 10 N force applied at theinput piston will produce a force of 1,000 N at the output piston. If the radius of the input piston is 2 cm, the radius of the output is
a) 200 cm,
b) .02 cm
area out / area in = 100 = pi Rout^2/ pi Rin^2 = R^2/(2^2)
R^2 = 400
R = 20
so ten times the radius for 100 times the area of course :)