Calculus
posted by Lee .
Evaluate
integral sign (x1/(2x))^2 dx=

(x  1/(2x))^2 = x^2  1 + 1/(4x)
((x1)/(2x))^2 = (x^2  2x + 1)/(4x^2) = 1/4  1/(2x) + 1/(4x^2)
Not sure which you meant, but either one is just a sum of terms, which are just powers of x. Just use the normal power rule (or lnx for 1/x) and things are easy. 
oops. Top one should end with 1/(4x^2)

Thanks
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