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the sum of the squares pf two postive consecutive even integers is 41. Find the integers.


    Is it?

    3 and 4
    4 and 5
    5 and 6


    its 4 and 5




    the number are even
    so let the first be x
    then the second is x+2

    x^2 + (x+2)^2 = 41
    x^2 + x^2 + 4x + 4 = 41
    2x^2 + 4x - 37 = 0

    No integer solution

    We could tell from the beginning that this problem has no solution
    the square of any even integer is even
    the sum of two even number is even, but 41 is odd, so NO WAY!

  • MATH PLEASE HELP -- Oopa~ -

    I misread the problem.

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