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College Algebra

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Given the equation x^2+y^2-8x-6y=0
(a) Write the equation in standard form.
(b) State the center, radius, and intercepts.

  • College Algebra -

    to get the standard form, regroup so you can look for perfect squares:

    (x^2 - 8x) + (y^2 - 6y) = 0

    Now add what you need to both sides:

    (x^2 - 8x + 16) + (y^2 - 6y + 9) = 16 + 9
    (x-4)^2 + (y-3)^2 = ^2

    I think you can probably extract the answers to (b) from that. no?

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