College Algebra

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Given the equation x^2+y^2-8x-6y=0
(a) Write the equation in standard form.
(b) State the center, radius, and intercepts.

• College Algebra -

to get the standard form, regroup so you can look for perfect squares:

(x^2 - 8x) + (y^2 - 6y) = 0

Now add what you need to both sides:

(x^2 - 8x + 16) + (y^2 - 6y + 9) = 16 + 9
(x-4)^2 + (y-3)^2 = ^2

I think you can probably extract the answers to (b) from that. no?

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