College Algebra
posted by sunny .
Given the equation x^2+y^28x6y=0
(a) Write the equation in standard form.
(b) State the center, radius, and intercepts.

to get the standard form, regroup so you can look for perfect squares:
(x^2  8x) + (y^2  6y) = 0
Now add what you need to both sides:
(x^2  8x + 16) + (y^2  6y + 9) = 16 + 9
(x4)^2 + (y3)^2 = ^2
I think you can probably extract the answers to (b) from that. no?
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