Calculus
posted by Untamed .
Simplify. State the nonpermissible values.
(3t^2+3t6/2t^22t4)(4t^2+4t24/3t^2+6t9)
This is the way I tried solving this:
3t(t1)6(t1)/2t(t1)4(t1)*4t(t2)12(t2)/3t(t+1)9(t1)
(3)(t)(t1)(2)(3)(t1)/(2)(t)(t1)(2)(2)(t1)*(2)(2)(t)(t2)(2)(2)(3)(t2)/(3)(t)(t1)(3)(3)(t1)
After cancelling out all the terms I am left with:
(2)(t2)(t2)/(t1)(t1)
^ I cant cancel anything off now. But the answer is supposed to be :
2(t+2)/t+1
^ How do I get that answer?

(3t^2+3t6)(4t^2+4t24)
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(2t^22t4)(3t^2+6t9)
3(t^2+t2)(4)(t^2+t6)
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2(t2)(t+1)(3)(t+3)(t1)
3(t+2)(t1)(4)(t+3)(t2)
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2(t2)(t+1)(3)(t+3)(t1)
(2) (t+2) / (t+1)
2 
Thank you so much Damon :)

You are welcome.
By the way that is undefined if t = 1 so I suppose that might be what is meant by "nonpermissible" 
Thank you and yeah nonpermissible is another word for restrictions.