Algebra
posted by Anonymous .
Suppose a 2% acid solution is mixed with a 3% acid solution. Find the percent of acid in each mixture.
a mixture that contains an equal amount of 2% acid solution and 3% acid solution
a mixture that contains 3 times more 2% acid solution than 3% acid solution

.02*V+.03V=2V*percent
percent= 2.5
.02*3V+.03V=4V*percent
percent= (.06+.03)/4=9/4 percent or 2.25 percent
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