Physics
posted by April .
A 8.22 kg block initially at rest is pulled to the
right along a horizontal, frictionless surface by
a constant, horizontal force of 16.8 N.
Find the speed of the block after it has
moved 2.3 m.
Answer in units of m/s

First compute the acceleration,
a = F/m = 2.044 m/s^2
V = s 
First compute the acceleration,
a = F/m = 2.044 m/s^2
Then use
V(final) = sqrt(2 a X)
where X is the distance travelled.
You could also use:
Work done on block = F*X
= final kinetic energy,
= (1/2)M Vfinal^2.
and then solve for Vfinal.
Vfinal = sqrt[2*(F/M)*x]
You will get the same result.
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