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The length of the fence of a trapezium-shaped field ABCD is 130m and side AB is perpendicular to each of the parallel sides AD and Bc.if BC=54m,CD=19m and AD=42m,find the area of the field.

  • math -

    The only missing side is AB

    AB + 54 + 19 + 42 = 130
    AB = 15

    That's the height. So area

    a = 15 * (54+52)/2

  • math -

    post it.

  • math -

    in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

  • math -

    in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

  • math -

    in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

  • math -

    720m

  • math -

    donot know

  • math -

    Find the area if ab =31 a

  • math -

    720

  • math -

    720

  • math -

    795 m2

  • math -

    720m2

  • math -

    720msq

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