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A chandelier of mass 250 kg is hung vertically from a ceiling using a 1.25 m long brass rod of square cross-section of sides 0.4 cm each. How much will the rod stretch when the chandelier is hung? By what factor is the minimum breaking load greater than the weight of the chandelier?

  • physics -

    The cross sectional area is
    A = 0.16 cm^2 = 1.6*10^-5 m^2

    The stress in the road is
    sigma = M*g/A = 1.53*10^8 N/m^2

    The amount of stretch is
    delta L = L*sigma/E

    where E is Young's modular for brass.

    The breaking load is
    P = A* sigmau

    where sigmay is the yield stress for brass.

    You will have to look up the modulus and yield stress values. They want you to compute the factor P/(M*g)

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