# MAth

posted by .

The sum of four consecutive integers is at least 114. Find the smallest possible values for these numbers.

HOW YOU DO THIS?

• MAth -

Let x = first integer
Then x + 2 = next integer
x + 4 = third integer
x + 6 = fourth consecutive integer

x + x + 2 + x + 4 + x + 6 > 114

4x + 12 > 114

4x > 102

• MAth -

thanks

• MAth -

so the first number would be 25.50
then 2nd would be 27.50

• MAth -

Ray -- that can't be right. The directions state that these are EVEN numbers.

• MAth -

is that correct

• MAth -

i don't get tell me please

• MAth -

102 / 4 = 25.5

The nearest even number is 26. That must be the

Check it out: 26 + 28 + 30 + 32 = ?

Aren't these the smallest possible values for these numbers?

• MAth -

• MAth -

But look consecutive numbers are Numbers which follow each other in order, without gaps, from smallest to largest.

12, 13, 14 and 15 are consecutive numbers.

THEY ARE NOT EVEN

IT SHOULD BE WITHOUT GAPS

• MAth -- oops! -

I'm sorry. I thought they were supposed to be even numbers. I apologize.

You're right, there should be no gaps.

• MAth -

ok

• MAth -

Let's start again. (I think I've read the problem correctly this time.)

x + x + 1 + x + 2 + x + 3 > 114

4x + 6 > 114

4x > 108

x = 27

Check: 27 + 28 + 29 + 30 = 114

• MAth -

thank you

• MAth -

You're welcome.

And again -- I'm sorry I steered you wrong.

The few times I taught math, I offered my students extra credit whenever they saw that I'd made a stupid mistake like this.

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