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5 mg iodine 131 its half life is 8.1 days what is the time when 1% remain

  • chemistry -

    k = 0693/t1/2
    Solve for k and substitute into the equation below.

    ln(No/N) = kt
    Use 5mg for No.
    Use 1% x 5 = 0.05 for N.
    k from above.
    Solve for t.
    t will be in days if you used 8.1 days for the half-life.

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