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What is the concentration (m) of a solution that consists of 48 grams of copper (2) acetate dissolved in 645 mL of solution?

  • chemistry -

    What's the formula for copper(2) acetate?

    Cu(CH3CO2)2

    Now, what's the mol weight?

    Cu = 63.55
    C = 12.01
    H = 1.008
    O = 16.00

    so, 1 mol = 63.55 + 2(12.01 + 3.024 + 12.01 + 32) = 181.638

    Now things get easy.

    You have 48/181.638 = 0.264 mol of cupric acetate

    so, your solution is .264mol/.645L = .409M

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