Physics

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a bomb is dropped from an airplane travelling horizontally with a speed of 300 mi/hr if the airplane is 10000ft. above the ground, how far from the target must it be released, neglect friction?

  • Physics -

    d = Vo*t + 0.5g*t^2 = 10.000 Ft.
    0 + 4.9t^2 = 10,000,
    t^2 = 2041,
    t = Tf = 45.2 s. = Fall time = Time in
    flight.

    Dx = Xo * Tf = 300 m/s * 45.2 s. = 13,553 Ft.= Dist. it should be released from target.

  • Physics -

    Correction:

    d = Vo*t + 0.5g*t^2 = 10,000 Ft.
    0 + 16t^2 = 10,000,
    t^2 = 625,
    t = 25 s.



    X0=300 mi/h * 1h/3600 s. = .0833 mi/s.

    Dx = 0.08333 mi/s * 25s = 2.083 mi =
    3333 m.

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