prealgebra
posted by Cass .
Find the product: (4k^5)(2k)^3
Is it 32k^8 or 32k^2
I don't know rather to add or subtract the 5 & 3.

The correct answer is 32k^8
 When you multiply powers with the same base, you keep the base and ADD the exponents.
 For the second multiplier, note that the both the 2 and the k would be cubed, whereas in the first multiplier only the k get raised to the 5th.
so you would (4)(k^5)(2)^3 (k^3)
= (4)(k^5)(8)(k^3)
= 32 k^8