A 30.0 KG LOAD IS BEING RAISED BY A FORCE OF 180N USING THE IDEAL PULLEY ARRANGEMENT SHOWN IN FIG, WHAT IS THE ACCELERATION OF THE LOAD?
PLEASE HELP
Ple4ase do not use all-caps here.
It is discourteous, like yelling in someone's ear.
Are you sending your questions by cell phone? Take a little extra time and use the shift key.
As far as your question is concerned, we cannot see your figure. You will have to describe the configuration.
If there is no friction and pulley inertia is ignored, you can use
a = F/m
To determine the acceleration of the load, we can utilize Newton's second law of motion. This law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.
First, let's break down the given information:
- Mass of the load (m): 30.0 kg
- Force applied (F): 180 N
Now, we can use Newton's second law:
F = m * a
where F is the net force, m is the mass, and a is the acceleration.
Rearranging the equation to solve for acceleration (a):
a = F / m
Plugging in the values we have:
a = 180 N / 30.0 kg
Calculating the value:
a = 6.0 m/s²
Therefore, the acceleration of the load is 6.0 m/s².