prealgebra
posted by Linda .
find the product: (4k to the 5th power)(2k)to the 3rd power. 5th power is inside the parenthesis and the 3rd is outside the parenthesis.
Is it 32k to the 8th power or 32k to the 2nd power?

(4k^5)(2k)^3
4^5 k^5 (2)^3 k^3
1024(8) k^8
8196 k^8
Now, if you meant
4(k^5)(2k)^3
Then you do indeed have
32k^8
When you have minus signs in the coefficient, they do not affect the exponents. Multiplying powers means add exponents. To get k^2 = k^(53), you'd have to have
4k^5(2k)^3
= 4/8 k^2
Then you'd have to take a negative power of 2, as well, making it a fraction.