Algebra II
posted by Gaby .
Please write y=x622x+3 in vertex form. Help would be appreciated thank you :)

y = x^2  2x + 3
y = (x^2 + 2x) + 3
now add 1 in the parens to make a perfect square
y = (x^2 + 2x + 1) + 1 + 3
y = (x+1)^2 + 4
y4 = (x+1)^2
For yk = a(xh)^2
the vertex is at (h,k)
so, your vertex is at (1,4)
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