Algebra II

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Please write y=-x62-2x+3 in vertex form. Help would be appreciated thank you :)

  • Algebra II -

    y = -x^2 - 2x + 3
    y = -(x^2 + 2x) + 3
    now add 1 in the parens to make a perfect square

    y = -(x^2 + 2x + 1) + 1 + 3
    y = -(x+1)^2 + 4
    y-4 = -(x+1)^2

    For y-k = a(x-h)^2
    the vertex is at (h,k)

    so, your vertex is at (-1,4)

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