pre calculus
posted by anon .
graph the function below. Determine the domain, range and horizontal asymptote. f(x) = (3/4)^x  1

as with all exponentials, the domain is all real numbers.
All exponential curves look basically alike. If n > 1, n^x curves up to the right.
If n < 1 the graph curves down to the right.
n^x always has the xaxis as an asymptote.
Note that n must be positive, since n^x = e^(x ln n) and ln is not defined for n<0.
So, the above graph looks like e^x, but is flipped upside down because of the negative sign.
Then the graph is shifted down one unit, so it has y=1 as the asymptote.
It rises steeply from the left, goes through (0,1) and approaches the line y = 1 from below. 
sorry  goes through (0,2)

It's ok figured that out on my own :)