Math

posted by .

Differentiate 1/tanx

I got -sec^2 / tan^2x, which is correct, but the answers said I could also simplify this to -cosec^2. How would you do that?

Thanks =)

  • Math -

    -sec^2/tan^2 = -sec^2 * cos^2/sin^2 = -1/sin^2 = -csc^2

  • Math -

    also, just as
    tan' = sec^2
    cot' = -csc^2 as you proved

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Integration

    Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct?
  2. calculus

    find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may have some challenging algebra to simplify it. Use the chain rule. Let y(u) = ln u u(x) = sec x + tan x …
  3. Pre-Cal

    Perform the addition or subtraction. tanx - sec^2x/tanx tan^2(x)/tan(x) - sec^2x/tanx = tan^2x sec^2x / tanx then I use the identity 1+tan^2u=sec^2u I do not know what to do at this point.
  4. trigonometry (please double check this)

    Solve the following trig equations. give all the positive values of the angle between 0 degrees and 360 degrees that will satisfy each. give any approximate value to the nearest minute only. a.) ( I got confused doing this 1 can you …
  5. calculus

    Did I do this problem right? Find the first and second derative-simplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'= xsec^2 x + tanx y"= (x)(2secx)(secxtanx)+sec^2 x + sec^2 x y"=2xsec^2 x tanx + 2 sec^2 x
  6. GENRAL MATHS

    PROVE THAT (1+COT A+TAN A)(SIN A-COS A)=SEC A\COSEC A-COSEC A\SEC A
  7. Calculus

    I think I have the correct answers for the following problems. For anyone who has the time I would appreciate it if you could tell me if I am correct/incorrect. Thank you. 1). Differentiate ã(x)sin x = (2xcosx+sinx)/2ã(x) 2). …
  8. Calc

    Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x-1)(tanx) dx then i did a u …
  9. Calc

    Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x-1)(tanx) dx then i did a u …
  10. Calculus

    Int tanx sec^2x dx can be taken as (by putting it in form of Int xdx) Int secx.secx tanx dx=(sec^2x)/2 Int tanx.sec^2x dx=(tan^2)/2. Which one is correct and why is the difference?

More Similar Questions