precalc
posted by 95 .
Rewrite 3y^2 + 6y + 108x  969=0 in standard form, show work.

That's pretty much in standard form.
ax^2 + bxy + cy^2 + dx + ey + f = 0
3y^2 + 108x + 6y  969 = 0
Now if you want a "standard" form for a parabola xh = a(yk)^2, try this:
108x = 3y^2  6y + 969
108x = 3(y^2 + 2y + 1) + 972
x = 1/36 (y+1)^2 + 9