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Rewrite 3y^2 + 6y + 108x - 969=0 in standard form, show work.

  • precalc -

    That's pretty much in standard form.

    ax^2 + bxy + cy^2 + dx + ey + f = 0

    3y^2 + 108x + 6y - 969 = 0

    Now if you want a "standard" form for a parabola x-h = a(y-k)^2, try this:

    108x = -3y^2 - 6y + 969
    108x = -3(y^2 + 2y + 1) + 972
    x = -1/36 (y+1)^2 + 9

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