geometry
posted by damon .
a regular hexagon is composed of 12 congruent 30,60,90 degree triangles. if the length of the hypotenuse of one of those triangles is 18 square root 3 find the perimeter of the hexagon

let x be the base of one of those triangles.
cos 60° = x/(18√3)
x = 18√3 cos 60°
= 18√3(√3/2) = 9
but x would be 1/2 of one of the sides of the hexagon
so each side is 18
and the perimeter = 6(18) or 108