Solve by completing the square:
x^2-6x+3=0
please take me step by step
Remember that (a-b)^2 = a^2 - 2ab + b^2
So, if you have x^2 - 6x you need half of the 6 to complete the square:
x^2 - 6x + 9 - 9 + 3 = 0
(x-3)^2 - 6 = 0
(x-3)^2 = 6
So, you can see that
x-3 = ±√6
so,
x = 3 ± √6