calculus
posted by piyatida .
verify the Intermediate Value Theorem if F(x)=squre root of x+1 and the interval is [3,24].

The intermediate value theorem states: If F(x) is a realvalued continuous function on the interval [a, b], and u is a number between f(a) and f(b), then there is a c value in the interval [a, b] such that f(c) = u.
In your case, a = 3, b = 24, f(a) = 2 and f(b) = 5
For any number between 2 and 5, let's say 4, there is an x value such that f(x) = 4. That value is 15