posted by Alissa .
Use the given information about a polynomial whose coefficients are real numbers to find the remaining zeros.
Zeros: -8 + 11x(can't put this sign in looks like ii with slash over)i, -7 + 17i, 16 - isqrt 2
You know that since the roots come in conjugate pairs, there will be
-7 + 17i and -7 -17i
16 - isqrt2 and 16 + isqrt2
so the factors will be
(x^2 - 14x + 338) that's (x^2 -2*7x + 17^2 + 7^2)
(x^2 - 32x + 258) that's (x^2 - 2*16x + 16^2 + sqrt2^2)
and the other pair you can figure out. I can't tell what you mean.
Hmm. I think that's +14x in the 1st case -(2*-7)