# Algebra

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Algebraically at what temp is Celsius 1/4 that of Fahrenheit??

ie C = 1/4 F

• Algebra -

TF = Fahrenheit temperature

TC = Celsius temperature

TF = ( 9 / 5 ) * TC + 32

TF = ( 9 / 5) * ( 1 / 4 ) + 32

TF = ( 9 / 20 ) + 32

TF = 9 / 20 + 640 / 20

TF = 649 / 20

TF = 32.45

( 1 / 4 ) ° C = 32.45 ° F

• Algebra -

Hmmm. I interpreted it to mean
Find the temperature where C temperature is 1/4 the F

C = 1/4 (9/5 C + 32)
4C = 9/5 C + 32
20C = 9C + 160
11C = 160
C = 14.545

F = 9/5 * 14.54 + 32 = 58.18

58.18 = 4*14.545

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