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okay so i made arctan(-4/3) = x
so im solving for sin(x)
and x= arctan(-4/3)
so then tanx = -4/3

and now im stuck i don't know what to do after that

  • PRE-CALC -

    Draw the right triangle (3,4,5)
    3^2+4^2 = 9+16 = 25 = 5^2
    angle A = atan(4/3)
    sin A = 4/5
    now look for quadrant
    tan = -4/3 in quadrant 2 and in quadrant 4
    in quadrant 2 sin A = 4/5
    in quadrant 4 sin A = -4/5

  • PRE-CALC -

    just draw the triangle
    tan = y/x
    sin = y/h

    h = 5 (3-4-5 triangle!)

    principal value of arctan(-4/3) is in QIV.

    sin = -4/5

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