The density of an elemental gas is 1.7824 g/L at STP. What is the molar mass of the element?

What is the new volume, in milliliters, of the balloon if remains constant and the balloon is very elastic?

To find the molar mass of the element, we can use the ideal gas equation:

PV = nRT

Where:
P = pressure (at STP, it is 1 atm)
V = volume (given as 1 L)
n = number of moles
R = gas constant (0.0821 L·atm/mol·K)
T = temperature (at STP, it is 273.15 K)

Rearranging the equation to solve for n:

n = PV / RT

Given that the density of the gas is 1.7824 g/L, we can convert this to moles using the molar mass (M) of the gas:

n = density / M

Combining these equations, we can solve for the molar mass:

M = density / (PV / RT)

Plugging in the values:

M = 1.7824 g/L / (1 atm * 1 L / mol * 0.0821 L·atm/mol·K * 273.15 K)

M = 1.7824 g/L / (0.0821 * 273.15 mol/K)

Calculating this gives us:

M ≈ 28.98 g/mol

Therefore, the molar mass of the element is approximately 28.98 g/mol.

To find the molar mass of the element, we need to know the density of the gas and its molar volume at STP.

STP (standard temperature and pressure) is defined as a temperature of 0 degrees Celsius (273.15 K) and a pressure of 1 atmosphere (atm).

Given that the density of the elemental gas at STP is 1.7824 g/L, we can use this information to calculate the molar mass.

The molar volume at STP is the volume occupied by one mole of gas at STP conditions, which is approximately 22.414 L/mol.

To calculate the molar mass, we can use the formula:

Molar mass = (Density x Molar volume) / 1000

Plugging in the given values:

Molar mass = (1.7824 g/L x 22.414 L/mol) / 1000

Molar mass = 0.04 g/mol

Therefore, the molar mass of the element is 0.04 g/mol.

1 mole of the gas will occupy 22.4 L at STP. So mass = volume x density. You have density and volume, solve for mass of 1 mole (which of course is molar mass).