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A soccer ball of mass 450 grams is initially moving horizontally east at 12 m/s. You kick it so that it moves horizontally north at 13 m/s. The collision lasts 0.04 s. Find the magnitude and direction of the average force you apply to the ball.

|F| =

Angle from East =

  • physics -

    Divide the momentum change vector by 0.04 s.

    The magnitude of the momentum change vector is
    sqrt[(12)^2 + (13^2] = 17.69 N*s
    Next, do the division.

    The direction is the direction of the momentum change.
    arctan13/12 = 47.3 degrees from east

  • physics -

    not right

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