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A block of mass of 24.0 kg is sitting on a frictionless surface. If the block is initially at rest, and a force of 3.0 N parallel to the surface is applied for 5.0 seconds, what is the final speed of the block?.

  • Physics -

    The acceleration is given by
    a = F/m = 1/8 m/s^2

    The distance it moves in t = 5.0 s is

    X = (1/2)*a*t^2
    = (1/16)*25 = 1.563 m

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