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find the are of the surface of the part of the sphere (x^2)+(y^2)+(z^2)=4 that lies above the plane z=4

  • calculus -

    Something fishy here.
    the sphere has centre at (0,0,0) and radius 2
    so it won't even reach the plane given by z=4

    I guess we could say the surface area which lies above z=4 would be zero.

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