Calc
posted by Anonymous .
find d^2y/dx^2 of x^2/3 + y^2/3 =1
(implicit differentiation)

Differentiate both sides with respect to x, with y considered a function of x.
(2/3)/x^1/3 + [(2/3)/y^1/3] dy/dx = 0
dy/dx = [y/x]^1/3
Then do it again.
d^2/dx^2 = .......
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