Calculate the heat transferred when a 8 g of iron nail is cooled from 50oC to 18oC. The specific heat of iron is 0.45 J/goC.
heat lost by Fe =q
[mass Fe x specific heat Fe x (Tfinal-Tintial)=q
To calculate the heat transferred, we can use the formula:
Q = m * c * ΔT
Where:
Q = heat transferred (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/goC)
ΔT = change in temperature (in oC)
In this case, the mass of the iron nail is given as 8 g, the specific heat capacity of iron is given as 0.45 J/goC, and the change in temperature is given as 50oC - 18oC = 32oC.
Substituting the values into the formula:
Q = 8 g * 0.45 J/goC * 32oC
Calculating this expression:
Q = 115.2 J
Therefore, the heat transferred when the iron nail is cooled from 50oC to 18oC is 115.2 joules.