Precalculus
posted by nessa .
I want to make sure this is right.
the inverse of f(x)=(3x+2)/(2x1)
I got f^1(x)=(x2)/(2x3).
if its right how do i check the answer to see if it is right. also would the domain of f be D=all real numbers except 1/2. And I do not know how to get the range for f^1

Precalculus 
Henry
y = (3x+2) / (2x1),
x = (3y+2) / 2y1),
Cross multiply:
3y + 2 = 2xyx,
3y  2xy = x2,
y(32x) = x 2,
y = (x2) / (2x3).
2x3 = 0,
2x = 3,
X = 3/2.
Domain = All real values of X except
3/2.
Range = All values of y resulting from inputs (x) within the domain.
Infinity < X < +Infinity.
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