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C2H6 --> 2CH3
at a temperature where the half-life is 21 minutes.

If the initial concentration is 8.0 mM, what would the concentration be after 46.0 minutes?

How long would it take to convert 95% of C2H6 at this temperature?

  • Chemistry -

    Fist, solve for k.
    k = 0.693/t1/2.

    The b part of the question is solved with the following.
    Set No = 8.0 mM
    Solve for N. Units will be in mM.
    Substitute k from the first part.
    ln(No/N) = kt

    For c part.
    Use the same equation as part b but us No = 100
    N = 5
    k form part a
    Solve for t.
    Post your work if you get stuck.

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