posted by B .
If 215.0 mL of water are added to a 237 mL sample of a 1.702 M dextrose solution, what is the new molarity of dextrose in the resulting solution?
1.702M means 1.702 moles/liter of solution
so, since we have only .237 liters, we have
1.702*.237 = 0.4033 moles of dextrose
adding 215 ml of water increases the volume to .452 liters
so, the new molarity is .4033/.452 = 0.892M