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If 215.0 mL of water are added to a 237 mL sample of a 1.702 M dextrose solution, what is the new molarity of dextrose in the resulting solution?

  • chemistry -

    1.702M means 1.702 moles/liter of solution

    so, since we have only .237 liters, we have
    1.702*.237 = 0.4033 moles of dextrose

    adding 215 ml of water increases the volume to .452 liters

    so, the new molarity is .4033/.452 = 0.892M

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