# Calculus

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definite Integrals (using fundamental Theorem)
Evaluate
from -1 to 2(x^2 - 4x)dx

• Calculus -

[x^3/3 - 2 x^2] @ 2
MINUS
[x^3/3 - 2 x^2] @ -1
= [8/3 - 8] - [-1/3 -2]
= -16/3 + 7/3 = -3

• Calculus -

Thank you so much. I had the integral part, but was off on the rest. :)

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