college algebra

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I think this is an exponential equation.
I can not figure out how to put the equation into the TI-84 to get the approximate form

3/5 ln(5x-1)+1 =1.4 subtract 1 from
sides and divide
by 3/5
lh(5x-1)=0.6667 Put in logarithm form
e^0.6667=5x-1 add 1 to both sides
e^0.6667=5x Divide by 5

e^0.6667 +1/5 exact form

• college algebra -

I would leave the .66667 as 2/3, since your are talking about "exact" form

3/5 ln(5x-1)+1 =1.4
3/5 ln(5x-1) = .4
ln(5x-1) = 2/3
5x - 1 = e^(2/3)
5x = e^(2/3) + 1
x = (e^(2/3) + 1)/5 or (1/5)e^(2/3) + 1/5

your forgot to divide the first term by 5 and only divided 1 by 5

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