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posted by Carly Wednesday, November 30, 2011 at 9:35pm.
in quadrilateral ABCD AC is a diagonol, m<ACD=2x+4 and m<ACB=5x-11 what proves ABCD a rhombus
It's a rhombus if the diagonal bisects the angles. So, if 2x+4 = 5x-11 the ABCD is a rhombus
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