Chemistry

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Kc for the reaction of hydrogen and iodine to produce hydrogen iodide,
H2(g)+I2(g)f 2HI(g)
is 54.3 at 430C. What will the concentrations be at equilibrium if we start with 0.240M concentrations of both H2 and I2?

  • Chemistry -

    Set up an ICE chart.
    ............H2 + I2 ==> 2HI
    initial.0.240...0.240....0
    change......-x....-x.....2x
    equil...0.240-x..0.240-x..2x

    Substitute into Kc expression.
    Kc = 54.3 = (HI)^2/(H2)(I2)
    Solve for x and evaluate 0.240-x

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