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A cable lifts a 1220-kg elevator at a constant velocity for a distance of 39.7 m. What is the work done by the tension in the cable?

can someone help me with this the answer is supposed to be in joules i tried doing it by 1220(9.81)(39.7) = 475137J but that is not the answer can someone please explain it to me?

  • physics -

    475,137.54 or 475,138
    or
    475,000 J to three significant figures

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