calculus
posted by amy
find f(x 1) for the following function
f(x) = sqrtx^2  3/ 6x + 6

michael
Is the entire equation underneath the square root or just the numerator? If it is just the numerator then here is the answer:
[sqrt((x1)(x1)3)]/[6(x1)+6]
[sqrt(x^2 2x+13)]/[6x6+6]
[sqrt(x^2 2x2)]/6x
[sqrt(x1)^2]/6x
x1/6x
I added brackets to make it easier to distinguish between numerator and denominator. If the whole equation was underneath the square root then the answer would be:
sqrt((x1)^2)/6x
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