physics
posted by Anonymous .
a projectile is launched straight up with an initial velocity of 112 feet per second. how long would it take to reach 180 feet?

d = Vo*t + 0.5g*t^2 = 180,
112t  16t^2  180 = 0,
Divide both sides by 4:
28t  4t^2  45 = 0,
4t^2 + 28t  45 = 0.
X = 2.5s. Use Quadratic Formula and use
the smaller of the 2 solutions.
Respond to this Question
Similar Questions

intermediate algebra
A projectile is launched directly upward from the top of a 112  foot building with an initial velocity (speed) of 96 feet per second. This translates to the h(t) = 16t^2 + 96t + 112 where h(t) is the height of the projectile in feet … 
math
You are standing on a bridge over a creek, holding a stone 20 feet above the water. 1. You release the stone. How long will it take the stone to hit the water? 
math
A projectile is fired directly upward with a muzzle velocity of 860 feet per second from a height of 7 feet above the ground. a. Determine a function for the height of the projectile t seconds after it’s released. b. How long does … 
math
an object is launched from ground level with an initial velocity of 400 feet per second. To the nearest tenth off a second, how long does it take the object to reach a height off 650 feet? 
algebra
An object that is projected straight downward with initial velocity v feet per second travels a distance s vt 16t 2 =+ , where t =time in seconds. If Ramón is standing on a balcony 84 feet above the ground and throws a penny straight … 
algebra
An object that is projected straight downward with initial velocity v feet per second travels a distance s vt 16t 2 =+ , where t =time in seconds. If Ramón is standing on a balcony 84 feet above the ground and throws a penny straight … 
Algebra: Quadratic Functions
if a rocket is launched straight up into the air with an initial velocity of 112 feet per second, it's height after t seconds is given by the formula h = 112t  16t, where x represents the height of the rocket in feet: A. When will … 
Algebra
The function H(t) = 16t2 + vt + s shows the height H (t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second. Part A: The projectile … 
algebra
The height in feet of a projectile with an initial velocity of 96 feet per second and an initial height of 112 feet is a function of time in seconds given by h(t) = −16t2 + 96t + 112. (a) Find the maximum height of the projectile. … 
precalc
A projectile is launched from a platform 10 feet high with an initial velocity of 72 feet per second, The height h of the projectile at t seconds after launch is given by h = –16t2 + 72t + 10 feet.