posted by alaa .
A 5.30 kg package slides 1.57 m down a long ramp that is inclined at 11.8^\circ below the horizontal. The coefficient of kinetic friction between the package and the ramp is mu_k = 0.320
Calculate the work done on the package by the normal force.
If the package has a speed of 2.17 m/s at the top of the ramp, what is its speed after sliding the distance 1.57 m down the ramp?
Why the name changes?