Calculus
posted by Jane .
Use your calculator to approximate the integral using the method indicated, with n=100. Round your answer to four decimal places. sqrt(x+4)^dx between 4 and 0.

What method is "indicated"? Simpson's Rule? Trapezoidal Rule?
Is an exponent supposed to follow your ^ sign? I don't see one.
For n = 100 intervals, evaluate f(x) for every 0.04 change in x, from 0 to 4.
We don't know what calculator you have. You will have to use your own. 
thanks for your answer, there was typo on the question ... but I figured out the answer using excel spreadsheet for Simpson's rule.
Respond to this Question
Similar Questions

Calculus
Use the Midpoint Rule with the given value of n to approximate the integral. Round the answer to four decimal places. int_2^10 2 sqrt(x^2+5)dx text(, ) n=4 
Calculus
Use the Midpoint Rule with the given value of n to approximate the integral. Round the answer to four decimal places. int_2^10 2 sqrt(x^2+5)dx text(, ) n=4 
Calculus
Oil is leaking out of a ruptured tanker at a rate of r = 19e^(2t) gallons per hour. Write a definite integral that represents the total quantity of oil which leaks out of the tanker in the first 3 hours. Using your formula answer the … 
Calculus
1. Find the are between the curves y=e^x and y=4x^2 graphically. a.) set up the integral b.) include bounds rounded to three decimal places c.) use integral function on calculator 2. Find the area of the "triangular" region bounded … 
Calculus
Can someone explain to me how to do these? 
calculus help
use the midpoint rule with the given value of n to approximate the integral. round the answer to four decimal places. integral 0 to pi/2 2cos^3(x)dx, n=4 M4=? 
Calculus Help Please Urgent!!!
Use the Midpoint Rule with the given value of n to approximate the integral. Round the answer to four decimal places. integral from o to pi/2 (2cos^3(x))dx , n = 4 M4 = ? 
Math
Use Newtonâ€™s Method to approximate 3^(√7) to four decimal places. Use x1 = 2 as your seed. Round off intermediate iterates to five decimal places 
calculus
Use x=1/2 in the MacLaurin series for e^x to approximate 1/sqrt (e) to four decimal places. So far I have f^n(0)/n! (1/sqrt(e)1/2)^n) </= 1/10^4, but I don't know what to do from here.